12=-1/2((9.8)(t))^2+18+12

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Solution for 12=-1/2((9.8)(t))^2+18+12 equation: 



12=-1/2((9.8)(t))^2+18+12

We move all terms to the left:

12-(-1/2((9.8)(t))^2+18+12)=0



Domain of the equation: 2((9.8)t)^2+18+12)!=0

We move all terms containing t to the left, all other terms to the right

2((9.8)t)^2+12)!=-18

t∈R



We multiply all the terms by the denominator


-(-1+12*2((9.8)t)^2+18+12)=0



We calculate terms in parentheses: -(-1+12*2((9.8)t)^2+18+12), so:

-1+12*2((9.8)t)^2+18+12

determiningTheFunctionDomain
12*2((9.8)t)^2-1+18+12

We add all the numbers together, and all the variables

12*2((9.8)t)^2+29

Wy multiply elements

24t((+29

Back to the equation:

-(24t((+29)



We add all the numbers together, and all the variables

-(24t(29=0

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